X^2-56x+300=0

Solution for X^2-56x+300=0 equation:

X^2-56X+300=0

a = 1; b = -56; c = +300;
Δ = b2-4ac
Δ = -562-4·1·300
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-44}{2*1}=\frac{12}{2}
=6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+44}{2*1}=\frac{100}{2}
=50
$